Аргумент | Возможный тип | Описание |
$table | — | — |
$res = $this->db->query("SELECT `table_name` AS `c` FROM `information_schema`.`tables` WHERE `table_schema` = DATABASE()"); $tables = array(); foreach($res->rows as $row) { $tables[] = $row['c']; } if(in_array($table, $tables)) { return true; }else{ return false; }