| Аргумент | Возможный тип | Описание |
| $table | — | — |
$res = $this->db->query("SELECT `table_name` AS `c` FROM `information_schema`.`tables` WHERE `table_schema` = DATABASE()");
$tables = array();
foreach($res->rows as $row) {
$tables[] = $row['c'];
}
if(in_array($table, $tables)) {
return true;
}else{
return false;
}
